For the reaction 2Cu(s) + S(s) Cu2S(s) Ho and Go are negative and So is positive.

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For the reaction
2Cu(s) + S(s) → Cu2S(s)
∆Ho and ∆Go are negative and ∆So is positive.
a. At equilibrium, will reactants or products predominate? Why?
b. Why must the reaction system be heated in order to produce copper (I) sulfide?

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General Chemistry

ISBN: 978-1439043998

9th edition

Authors: Darrell Ebbing, Steven D. Gammon

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Question Posted: Mar 01, 2016 05:08 AM

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For the reaction 2Cu(s) + S(s) Cu2S(s) Ho and Go are negative and So is positive.

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a If G is negative then K must be greater than 1 Consequently the prod...View the full answer

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