Form factor of atomic hydrogen for the hydrogen atom is its ground state, the number density is
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Form factor of atomic hydrogen for the hydrogen atom is its ground state, the number density is n(r) = (πa03)–1 exp (– 2r/a0), where a0 is the Bohr radius. Show that the form factor is fG = 16/ (4 + G2a20)2.
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3 f 47 na Gr sin Gr exp 2ra dr 4Ga dx ...View the full answer
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