Question: How much heat is released when a mixture containing 10.0 g CS2 and 10.0 g Cl2 reacts by the following equation? CS2(g) + 3Cl2(g)
CS2(g) + 3Cl2(g) → S2Cl2(g) + CCl4(g);
∆H° = –230 kJ
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The equation is CS 2 g 3Cl 2 g S 2 Cl 2 g CCl 4 g H 230 kJ First ... View full answer
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