Question: An idealized velocity field is given by the formula V=4txi2t2yj+4xzk Is this flow field steady or unsteady? Is it two- or three-dimensional? At the point

An idealized velocity field is given by the formula V=4txi−2t2yj+4xzk
Is this flow field steady or unsteady? Is it two- or three-dimensional? At the point (x, y, z) = (–1, +1, 0), compute
(a) The acceleration vector and
(b) Any unit vector normal to the acceleration.

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