Question: If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 96 ft/sec, its height after t seconds

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 96 ft/sec, its height after t seconds is s(t)=32+96t-16t^2 ,
1) What is the maximum height the ball reaches?
2) What is the velocity of the ball when it hits the ground (height 0)

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1 The height function would be st 16t2 96t 32 ... View full answer

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