If F = x2ax + y2ay + (z2 1) az, find S F dS, where S

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If F = x2ax + y2ay + (z2 – 1) az, find ∫S F ∙ dS, where S is defined by p = 2, 0 < z < 2, 0 < Φ < 2, 0 < Φ < 2π.
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