Question: If f(x) = 1n x, then f(n) (x) = (-1)n-1 (n - 1)! / xn. Thus, the Taylor polynomial of order n based at 1

If f(x) = 1n x, then f(n) (x) = (-1)n-1 (n - 1)! / xn. Thus, the Taylor polynomial of order n based at 1 for 1n x is
1n x = (x - 1) - 1 / 2 (x - 1)2 + 1 / 3 (x - 1)3 + ...

How large would n have to be for us to know that |Rn(x)| ( 0.000005 if 0.8 ( x ( 1.2?

x1)+ R(x)

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