Question: If g(x) := x for x (0, 1), show that there does not exist a constant K such that |g(x)| < K|x| for all

If g(x) := √x for x ∈ (0, 1), show that there does not exist a constant K such that |g(x)| < K|x| for all x ∈ (0, 1). Conclude that the uniformly continuous g is not a Lipschitz function on [0, 1].

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