Question: If X is a normally distributed random variable with mean 97 and standard deviation 10, find x2 such that P(102 < X < x2) =
If X is a normally distributed random variable with mean 97 and standard deviation 10, find x2 such that P(102 < X < x2) = 0.05.
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X N97 10 2 P102 X x 005 P 005 P05 Z z 005 T... View full answer
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