Question: If Y has probability density function fY (y)=2y, 0 y 1 then E(Y) = 2/3 . Define the random variable W to be the squared
fY (y)=2y, 0≤ y ≤1 then E(Y) = 2/3 . Define the random variable W to be the squared deviation of Y from its mean, that is, W = (Y – 2/3) 2. Find E (W).
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