Question: In a Young's double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is A = 1.6 10-4 degrees when the

In a Young's double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is θA = 1.6 × 10-4 degrees when the magnitude of the electron momentum is pA = 1.2 × 10-22kg? m/s. With the same double slit, what momentum magnitude pB is necessary so that an angle of θB = 4.0 × 10-4 degrees locates the first-order bright fringes?

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According to Equation 271 the angle that locates the firstorder bright fringes m 1 is specified by sin d where is the wavelength and d is the separation between the slits The wavelength of the electron is the de Broglie wavelength which is given by hp Equation 298 where h is Plancks constant and p is the magnitude of the momentum of the electron Combining Equations 271 and 298 we find that the angle locating the first ... View full answer

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