Question: In problems, use integration by parts to derive the given formula. (a) sin x sin3x dx = -3/8 sin x cos3x + 1/8 cos
(a) ∫ sin x sin3x dx = -3/8 sin x cos3x + 1/8 cos x sin 3x + C
(b) ∫ cos 5x sin7x dx = -7/24 cos 5x cos 7x - 5/24 sin 5x 7x + C
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a u sin x dv sin3xdx du cos x dx v 13 cos 3x u cos x dv cos3xdx du sin ... View full answer
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