Question: In using the Kruskal-Wallis test, there is a correction factor that should be applied whenever there are many ties: Divide H by Here T =

In using the Kruskal-Wallis test, there is a correction factor that should be applied whenever there are many ties: Divide H by

Here T = t3 - t, where t is the number of observations that are tied for a group of tied scores. That is, find t for each group of tied scores, then compute the value of T, then add the T values to get ˆ‘T. For the example presented in this section, use this procedure to find the corrected value of H. Does the corrected value of H differ substantially from the value of 14.431 that was found in this section?

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