Question: Inductors in Series BDd Parallel. You arc given two inductors, one of self-inductance L. and the other of self-inductance L2. (a) You connect the two

Inductors in Series BDd Parallel. You arc given two inductors, one of self-inductance L. and the other of self-inductance L2.
(a) You connect the two inductors in series and arrange them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = L1 + L2.
(b) You now conneet the two inductors in parallel. again arranging them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = (1/L1 + 1/L2)-1.

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