Question: Let f : R R be periodic and a > 0. Suppose that f is Lipschitz of order a; that is, there is a constant
Let f : R R be periodic and a > 0. Suppose that f is Lipschitz of order a; that is, there is a constant M > 0 such that
for all x, h R.
a) Prove that
holds for each h R.
b) If h = Ï/2n+l, prove that sin2 kh > 1/2 for all k [2n-1, 2n].
c) Combine parts a) and b) to prove that
-3.png)
for» = 1, 2, 3,....
d) Assuming
-4.png)
(see Exercise 11.7.9), prove that if f is Lipschitz of order a for some a > 1/2, then Sf converges absolutely and uniformly on R.
e) Prove that if f: R R is periodic and continuously differentiable, then Sf converges absolutely and uniformly on R.
ST 1/2 2"-1 1/2 2"-1
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a Fix h R and k N By using the change of variables u x h du dx and a sum angle formula we ... View full answer
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