Question: Let f (x) = (x 1)10, p = 1, and pn = 1 + 1/n. Show that |f (pn)| < 103 whenever n >

Let f (x) = (x − 1)10, p = 1, and pn = 1 + 1/n. Show that |f (pn)| < 10−3 whenever n > 1 but that |p − pn| < 10−3 requires that n > 1000.

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