Question: Let f(x) = cos3 x - 1.25 cos2 x + 0.225. Find f'(x0) at that point x0 in [ / 2, ] where f(x0) =

Let f(x) = cos3 x - 1.25 cos2 x + 0.225. Find f'(x0) at that point x0 in [π / 2, π] where f(x0) = 0.

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