Question: Let f(x) = kx2 (1 x) if 0 < x < 1 and f(x) = 0 if x < 0 or x > 1.

Let f(x) = kx2 (1 – x) if 0 < x < 1 and f(x) = 0 if x < 0 or x > 1.
(a) For what value of k is f a probability density function?
(b) For that value of k, find P(X > ½).
(c) Find the mean.

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a For 0 x 1 we have fx kx 1x which is nonnegative if and only if k 0 Al... View full answer

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