Question: Let g1; g2; . . . ; gm be linear functional on a linear space X, and let S ={x X : gj(x) = 0,
S ={x X : gj(x) = 0, j = 1,2,..., m}=
-1.png)
Suppose that f ^ 0 is another linear functional such that such that f (x)= 0 for every x e S. Show that
-2.png)
Figure 3.20
The Fredholm alternative via separation
1. The set Z . {f} x, - g1(x), g2.x. . . . -gm.x X} is a subspace of Y . Rm+1.
2. e0 = (1,0,0, ¢¢¢, 0) m+1 does not belong to Z (figure 3.20).
3. There exists a linear functional 0 and Ï(z) = 0 for every z Z,
4. Let Ï (y) = l λTy where λ = λ0 , λ1,......λm) Y = (m+1). For every z Z.
5. λ0 > 0.
6. f (x). . mi=1 λigi (x); that is f is linearly dependent on g1g2 .......gm.
n kernel g/ f(x) eo 9(x)
Step by Step Solution
3.48 Rating (161 Votes )
There are 3 Steps involved in it
1 Consider the set 1 2 is the image of a linear mapping from to 1 and hence ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
914-M-N-A-O (532).docx
120 KBs Word File
