Question: Let vj = (vj1,. . . . . . . . .,Vjn) Rn, j = 1,. . . . . . ., n, be
and the determinant of the vj's is the number
det(v1...,vn) := del[vjk]n × n.
Prove that
Vol(P(v1...,vn)) = |det(v1,...,vn)|.
Check this formula for n = 2 and n = 3 to see that it agrees with the classical formulas for the area of a parallelogram and the volume of a parallelepiped.
P(v1..... Vn) = (Vi ++ I, Vn : tj [0, 1]),
Step by Step Solution
3.43 Rating (159 Votes )
There are 3 Steps involved in it
Let t 1 t n t 1 v 1 t n v n Then takes 0 1 n onto P... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
741-M-N-A-D-I (728).docx
120 KBs Word File
