Question: Let X1, . . ., Xn be a random sample from exponential distribution with a mean of y. Show that Y1 = min (X1, X2,

Let X1, . . ., Xn be a random sample from exponential distribution with a mean of y. Show that Y1 = min (X1, X2, . . ., Xn) has an exponential distribution with mean y/n. Also, find the pdf of Yn = max (X1, X2, . . ., Xn).

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