Question: Let X1, . . ., Xn be a random sample of size n from the geometric distribution for which p is the probability of success.
(a) Use the method of moments to find a point estimator for p.
(b) Use the following data (simulated from geometric distribution) to find the moment estimator for p:
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How will you use this information? [The pdf of a geometric distribution is f(x) = p(1 €“ p)x€“1, for x = 1, 2,. . .. Also μ = 1/p.]
2 5 7 43 18 19 16 22 4 34 19 21 23 6 2 7 12
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a Given we can equate the first sample ... View full answer
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