Model potential flow through the upper half of the symmetric diffuser shown below, the expansion angle is theta 18 5 deg Use a non square mesh and calculate and plot (a) The velocity distribution and (b) The pressure coefficient along the centerline (the bottom boundary) 2h...

The tangent of 185 is 0334 so L 3h and 31 r ...

Model potential flow through the upper-half of the symmetric diffuser shown below, the expansion angle is θ

Question:

Model potential flow through the upper-half of the symmetric diffuser shown below, the expansion angle is θ = 18.5°. Use a non-square mesh and calculate and plot
(a) The velocity distribution; and
(b) The pressure coefficient along the centerline (the bottom boundary).