Molecular bromine is 24 per cent dissociated at 1600 K and 1.00 bar in the equilibrium Br2
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Molecular bromine is 24 per cent dissociated at 1600 K and 1.00 bar in the equilibrium Br2 (g) = o 2 Br (g). Calculate
(a) Kat 25°C,
(b) ∆p3,
(c) Kat 2000°C given that L3.,H3= + 112 k] mol-lover the temperature range.
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a Brg b c Amount at equilibrium Mole fraction Partial pressure K 2Brg 024 P...View the full answer
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