Question: A parallel-plate capacitor has fixed charges + Q and Q. The separation of the plates is then double. (a) By what facto does the energy
(a) By what facto does the energy stored in the electric field change?
(b) How much work must be done in doubling the plate separation from d to 2d? The area of each plate is A.
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4 since the separation of the plates is doubled the d capacitance is reduced to half its original va... View full answer
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