A piston/cylinder has 2 lbm of R-134a at state 1 with 200 F, 90 lbf/in 2 and is then brought to saturated vapor, state 2,

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A piston/cylinder has 2 lbm of R-134a at state 1 with 200 F, 90 lbf/in 2 and is then brought to saturated vapor, state 2, by cooling while the piston is locked with a pin. Now the piston is balanced with an additional constant force and the pin is removed. The cooling continues to a state 3 where the R-134a is saturated liquid. Show the processes in a P-V diagram and find the work in each of the two steps, 1 to 2 and 2 to 3.

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CV R134a This is a control mass Properties from table F101 and 102 State 1 TP v07239 ... View full answer

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