Pr(D) = 0.2, Pr(N) = 0.8, Pr(P | D) = 0.95, and Pr(P | N) = 0.05.
Question:
In the above case, the test does not catch every sick person. Let D denote the event of an individual having the disease, N the event of not having the disease, and P the event of a positive result on the test. Find Pr(D | P) and Pr(D | Pc) (the probability that a person who did not test positive has the disease).
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First find PrP with the law of total probability PrP PrP D PrD PrP N PrN 095 02 005 ...View the full answer
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Related Book For
Modeling the Dynamics of Life Calculus and Probability for Life Scientists
ISBN: 978-0840064189
3rd edition
Authors: Frederick R. Adler
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