A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q =

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A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q = +2e, m = 4.0 u) are accelerated through the same potential difference and then enter the same region of uniform magnetic field B, moving perpendicular to B. What is the ratio of?

(a) The proton's kinetic energy K p to the alpha particle's kinetic energy K α and

(b) The deuteron's kinetic energy K d to K α? If the radius of the proton's circular path is 10 cm, what is the radius of?

(d) The alpha particle's path?

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Jan 21, 2011 05:54 AM

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A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q =

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a Since K qV we have K K as q 2K or KK 050 b Simil...View the full answer

Fundamentals of Physics

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