A rate constant is found to fit the expression k2 = (6.45 X 1013) e-(5375K)/T dm3 mol-3

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A rate constant is found to fit the expression k2 = (6.45 X 1013) e-(5375K)/T dm3 mol-3 s-1 near 25°C. Calculate G for the reaction at 25°C.

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Physical Chemistry

ISBN: 978-0716743880

7th Edition

Authors: Peter Atkins

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Question Posted: Mar 13, 2010 02:14 AM

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A rate constant is found to fit the expression k2 = (6.45 X 1013) e-(5375K)/T dm3 mol-3

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The Gibbs energy of activation is related to the rate constant ...View the full answer

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