Question: Repeat the procedure in Exercise 65 for the titration of 25.0 mL of 0.100 M NH3 (Kb = 1.8 10-5) with 0.100 M HCl.
Repeat the procedure in Exercise 65 for the titration of 25.0 mL of 0.100 M NH3 (Kb = 1.8 × 10-5) with 0.100 M HCl.
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At beginning of the titration only the weak base NH 3 is present As always solve for the pH using th... View full answer
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