Question: Show by a calculation (using the formula Go = -RT ln Keq) that a free-energy difference of 7.6 kJ mol-1 between the axial and equatorial

Show by a calculation (using the formula ∆Go = -RT ln Keq) that a free-energy difference of 7.6 kJ mol-1 between the axial and equatorial forms of methylcyclohexane at 25oC (with the equatorial form being more stable) does correlate with an equilibrium mixture in which the concentration of the equatorial form is approximately 95%.

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