Question: Show that each conditional statement in Exercise 9 is a tautology without using truth tables. In Figure 9 a) (p q) p b)
In Figure 9
a) (p ∧ q) → p
b) p → (p ∨ q)
c) ¬p → (p → q)
d) (p ∧ q) → (p → q)
e) ¬(p → q) → p
f) ¬(p → q)→¬q
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