Question: Show that if ak; bk {0; 1; . . . ; 9} and if a1/10 + a2/102 + + an/10n = b1/10 +

Show that if ak; bk ∈ {0; 1; . . . ; 9} and if
a1/10 + a2/102 +∙ ∙ ∙+ an/10n = b1/10 + b2/102+∙ ∙ ∙+ bm/10m ≠ 0;
then n = m and ak = bk for k = 1; . . . ; n.

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