Show that the ith row of B = A1v(1)xt is zero, where 1 is the largest value

Show that the ith row of B = A−λ1v(1)xt is zero, where λ1 is the largest value of A in absolute value, v(1) is the associated eigenvector of A for λ1, and x is the vector defined in Eq. (9.7).