Question: Show that the triangle in the plane with vertices (x1, y1), (x2, y2), and (x3, y3) has area equal to one-half the absolute value of

Show that the triangle in the plane with vertices (x1, y1), (x2, y2), and (x3, y3) has area equal to one-half the absolute value of the determinant

Show that the triangle in the plane with vertices (x1,

2 y2

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