Question: Show that the worst-case complexity in terms of comparisons of an algorithm that finds the maximum and minimum of n elements is at least [3n/2]
Show that the worst-case complexity in terms of comparisons of an algorithm that finds the maximum and minimum of n elements is at least [3n/2] − 2.
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We think of ourselves as observers as some algorithm for solving this problem is executed We do not care what the algorithms strategy is but we view i... View full answer
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