Question: Solve Exercise 8.11 with a right-triangle diagram. In Exercise 8.11 One thousand kilograms per hour of a 45 wt% acetone in- water solution is to

Solve Exercise 8.11 with a right-triangle diagram.

In Exercise 8.11

One thousand kilograms per hour of a 45 wt% acetone in- water solution is to be extracted at 25?C in a Continuous, countercurrent system with pure 1,1 ,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram:

(a) The minimum flow rate of solvent,

(b) The number of stages required for a solvent rate equal to 1.5 times the minimum, and

(c) The flow rate and composition of each stream leaving each stage.

Acetone, Weight Fraction Water, Weight Fraction Trichloroethane, Weight Fraction 0.60 Extract 0.13

The tie-line dataare:

0.27 0.50 0.04 0.46 0.40 0.03 0.57 0.30 0.02 0.68 0.20 0.015

Acetone, Weight Fraction Water, Weight Fraction Trichloroethane, Weight Fraction 0.60 Extract 0.13 0.27 0.50 0.04 0.46 0.40 0.03 0.57 0.30 0.02 0.68 0.20 0.015 0.785 0.10 0.01 0.89 Raffinate 0.55 0.50 0.35 0.10 0.43 0.07 0.40 0.57 0.03 0.30 0.68 0.02 0.20 0.79 0.01 0.10 0.895 0.005

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Subject Extraction of acetone A from water C by 1 1 2trichloroethane S at 25 o C Given 1000 kgh of 45 wt A in C Liquidliquid equilibrium data 10 wt A in raffinate Find Using a right triangle diagram a ... View full answer

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