Question: Solve for 0 2 41. Sin 2 + sin 3 = 0 43. cos 4 + cos 2 = 0

Solve for 0 ≤ θ 2π
41. Sin 2θ + sin 3θ = 0
43. cos 4θ + cos 2θ = 0

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41 sin sin when 2k or 2k Substituting 2 and 3 we have either 2 3 2k or 2 3 2k Solving e... View full answer

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