Solve the following problems for x(t). Compare the values of x(0+) and A(0-). For parts (b) through
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a. 7* + 5x = 48(t) x(0-) = 3 b. 3x + 30x + 63x = 56(t) x(0-) = * (0-) = 0 c. * + 14x + 49x = 38(t) x(0-) = 2 * (0-) = 3 d. * + 14% + 58x = 46(t) x(0-) = 4 * (0-) = 7
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a 7sXs 3 5Xs 4 Xs 257s 5 257s 57 xt 25 7 e 5t7 This gives x0 257 From the initial value theorem ...View the full answer
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