Question: A spacecraft is describing a circular orbit at an altitude of 930 mi above the surface of the earth. As it passes through point A,

A spacecraft is describing a circular orbit at an altitude of 930 mi above the surface of the earth. As it passes through point A, its speed is reduced by 40 percent and it enters an elliptic crash trajectory with the apogee at point A. Neglecting air resistance, determine the speed of the spacecraft when it reaches the earth??s surface at point B.

0968 = B V 930 mi

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Circular orbit velocity R 3960 mi 209088 106 ft TAO 930 mi 49104 x 106 ft ... View full answer

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