Generalizing Exercise 27, show that if a + b 0, then Q(a + b) = Q(a,
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Generalizing Exercise 27, show that if √a + √b ≠ 0, then Q(√a + √b) = Q(√a, √b) for all a and b in Q.
Data from Exercise 27
Prove in detail that Q(√3 +√7) = Q(√3,√7).
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