Let G be a finite group and let p be a prime dividing |G|. Let P be
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Let G be a finite group and let p be a prime dividing |G|. Let P be a Sylow p-subgroup of G. Show that N[N[P]] = N[P].
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Because NP is a normal subgroup of NNP conjugation of P by an element of NNP yields a subgroup of NP ...View the full answer
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