Question: With reference to Exercise 53, what is the situation if 1 < m < n and m does not divide n? Data from ex. 53

With reference to Exercise 53, what is the situation if 1 <  m < n and m does not divide n?

Data from ex. 53  

Show that in a finite cyclic group G of order n, written multiplicatively, the equation xm = e has exactly m solutions x in G for each positive integer m that divides n.

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There are exactly d solutions where d is the gcd of m and n Wo... View full answer

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