With reference to Exercise 53, what is the situation if 1 < m < n and m
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With reference to Exercise 53, what is the situation if 1 < m < n and m does not divide n?
Data from ex. 53
Show that in a finite cyclic group G of order n, written multiplicatively, the equation xm = e has exactly m solutions x in G for each positive integer m that divides n.
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There are exactly d solutions where d is the gcd of m and n Wo...View the full answer
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