Question: Working a bit harder than in Exercise 20, show that f (x) F[x] has no zero of multiplicity > 1 if and only if

Working a bit harder than in Exercise 20, show that f (x) ∈ F[x] has no zero of multiplicity > 1 if and only if f(x) and f'(x) have no common nonconstant factor in F[x].

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