In problem use Theorem 7 1 1 to find 1 f(t) f(t) (1 e 2t ) 2 Theorem 7 1 1 1 (a) L 1 n n 1, 2, 3, s a (b) L t (c) L e k (d) L sin kt (e) L cos kt 5 k s k k (f) L sinh kt (g) L cosh kt s2 k2 s2 k2

Question: In problem use Theorem 7.1.1 to find [1]{f(t)}. f(t) = (1 + e 2t ) 2 Theorem 7.1.1 1 (a) L{1} = - n!

In problem use Theorem 7.1.1 to find ℒ [1]{f(t)}.

f(t) = (1 + e^2t)²

Theorem 7.1.1

1 (a) L{1} = - n! n = 1, 2, 3, ... =-- s - a (b) L{t

1 (a) L{1} = - n! n = 1, 2, 3, ... =-- s - a (b) L{t"} (c) L{e"} k (d) L{sin kt} (e) L{cos kt} 5? + k? s? + k? k (f) L{sinh kt} (g) L{cosh kt} s2 k2 s2 k2

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