Question: Let Y = (X - v/) Show that if is a Weibull random variable with parameters v, , and , then is an exponential
Let
Y = (X - v/α)β
Show that if is a Weibull random variable with parameters v, α, and β, then is an exponential random variable with parameter λ = 1 and vice versa.
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If X is a Weibull random variable with parameters v and then the distribution function of X is ... View full answer
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