Assuming sufficient differentiability, show that (a) curl (u + v) = curl u + curl v (b)
Question:
Assuming sufficient differentiability, show that
(a) curl (u + v) = curl u + curl v
(b) div (curl v) = 0
(c) curl (fv) = (grad f) × v + f curl v
(d) curl (grad f) = 0
(e) div (u × v) = v • curl u - u • curl v
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Parts b and d are basic They follow from the definitions by direct ...View the full answer
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