Find e 0 25 and e 0 75 by linear interpolation of e x with x 0 0, x 1 0 5 and x 0 0 5, x 1 1, respectively Then find p 2 (x) by quadratic interpolation of e x with x 0 0, x 1 0 5, x 2 1 and from it e 0 25 and e 0 75 Compare the errors Use 4S values of e x

Question: Find e -0.25 and e -0.75 by linear interpolation of e -x with x 0 = 0, x 1 = 0.5 and x 0 =

Find e^-0.25and e^-0.75by linear interpolation of e^-x with x₀ = 0, x₁ = 0.5 and x₀ = 0.5, x₁ = 1, respectively. Then find p₂(x) by quadratic interpolation of e^-x with x₀ = 0, x₁ = 0.5, x₂ = 1 and from it e^-0.25 and e^-0.75.Compare the errors. Use 4S-values of e^-x.

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