Question: Let A = [ jk ] be an n n matrix with (not necessarily distinct) eigenvalues 1 , ,
Let A = [αjk] be an n × n matrix with (not necessarily distinct) eigenvalues λ1, · · · , λn. Show.
The polynomial matrix
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has the eigenvalues
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where j = 1,· · ·,n, and the same eigenvectors as A.
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To show that the polynomial matrix PA has the same eigenvectors as A and that its eigenvalues are given by Pj where j is an eigenvalue of A we need to ... View full answer
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