# Solve, showing details: y' 1 = 4y 2 + 5e t y' 2 = -y 1 - 20e -t y1(0) = 1, y2(0) = 0

Chapter 4, PROBLEM SET 4.6 #14

Solve, showing details:

y'_{1} = 4y_{2} + 5e^{t}

y'_{2} = -y_{1} - 20e^{-t}

y1(0) = 1, y2(0) = 0

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